Question 1078183
{{{h=x-3}}}
For the base area,
{{{A[b]=pi*x^2}}}
For the side area,
{{{A[s]=2pi*x*(x-3)}}}
So then together,
{{{A=A[b]+A[s]}}}
{{{A=2pi*x^2+2pi(x^2-3x)}}}
{{{A=2pi*x(2x-3)}}}