Question 1078106
slope of the desired line is -1/3, the negative reciprocal of 3
y-y1=m(x-x1), m slope, and (x1,y1) the coordinates
y+1=(-1/3)(x-1)
y=-(1/3)x-2/3
{{{graph(300,300,-10,10,-10,10,3x+2,(-1/3)x-(2/3))}}}