Question 1078093

the equation in point-slope form: {{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is y-intercept

the equation of the line passing through 
P({{{1}}}, {{{6}}}) with slope {{{m =2/3}}} will be:

{{{y=mx+b}}}...substitute given {{{m}}}, given  {{{x}}} and {{{y}}} coordinates of the point P({{{1}}}, {{{6}}}) so we can calculate {{{b}}}

{{{6=(2/3)*1+b}}}

{{{6-(2/3)=b}}}

{{{18/3-2/3=b}}}

{{{16/3=b}}}

so, your equation is: {{{y=(2/3)x+16/3}}}