Question 1078025
Multiply the first equation by 6,
{{{2x+3y=0}}}
Multiply the second equation by 20,
{{{10x+4y=44}}}
From eq. 1,
{{{10x+15y=0}}}
{{{10x=-15y}}}
So substituting into the second equation,
{{{-15y+4y=44}}}
{{{-11y=44}}}
Solve for y then use either equation to solve for x.