Question 1024456
For the value of exports to reach 5.5 billion, we have:
5.5=1.8208 e^.3387x 
3.02065=e^.3387x
ln 3.02065=ln e^.3387x=.3387x
.3387x=1.1054721272885505026483318585694
x=3.2638681053692072708837669281647 years after 1998, which equals 2001.2639.

a)The average score on the original exam was:
95-7log(t+1)=95-7log(0+1)=95-7log1=95-0=95
b)After 6 months:
f(6)=95-7log(6+1)=95-7log7=95-5.92=89.08
c)After 18 months:
f(18)=95-7log(18+1)=95-8.95=86.04
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