Question 1077767
Let n and 3n be the number of nights stayed at A and B, respectively . Then:
(599.98+100n)/n=2399.94/3n
3(599.98+100n)=2399.94
1799.94+300n=2399.94
300n=600
n=2
599.98/2=299.99
Option A is 299.99/night;Option B is 399.99/night. So, option C is 349.99/night. 4 nights @ 349.99/night=$1399.96 as the total cost of C. ☺☺☺☺