Question 1077800
the equation of the line that is tangent to the circle {{{(x-2)^2 + (y-4)^2 = 289}}} is {{{x=-15}}}

{{{drawing( 600, 600, -30, 30, -30, 30,
line(-15,-25,-15,25),
 graph( 600, 600, -30, 30, -30, 30, -sqrt(289-(x - 2)^2)+4,sqrt(289-(x - 2)^2)+4)) }}}