Question 1077779

let's two numbers be {{{x}}} and {{{y}}}

the ratio of {{{x}}} to {{{y}}} is {{{3/4}}}: 

{{{x/y=3/4}}}......eq.1

and the sum of two numbers is {{{1001}}}:

{{{x+y=1001}}}.........eq.2...solve for {{{x}}}

{{{x=1001-y}}}.......eq.2a

substitute {{{x}}} in eq.1

{{{(1001-y)/y=3/4}}}......eq.1.....solve for {{{y}}}

{{{4(1001-y)=3y}}}

{{{4004-4y=3y}}}

{{{4004=3y+4y}}}

{{{4004=7y}}}

{{{4004/7=y}}}

{{{y=highlight(572)}}}

go to {{{x=1001-y}}}.......eq.2a, substitute {{{y}}}

 {{{x=1001-572}}}
 {{{x=highlight(429)}}}

so, your numbers are: {{{highlight(429)}}} and {{{highlight(572)}}}