Question 1077763
P=10 
SOLUTI0N
a=P-3
r=3P+5/P-3
using the 3rd term
p-3*{{{3P+5/P-3}}}^2=18P-5
Solving we have
9p^2+30P+25=18P^2-59p+15
Solving the quadractic eqn
p=-1/9  OR 10 WE ARE ONLY USING THE POSITIVE VALUE.