Question 1077745
<pre>
{{{ 2x+3y= 9 999 999 999 999 }}}

Solve for y

{{{3y= 9 999 999 999 999-2x }}}

{{{y= 3 333 333 333 333 -2x/3 }}}

x must be a multiple of 3

Let x = 3n, where n is a positive integer

{{{y= 3 333 333 333 333-2n }}}

n is largest when y is smallest, so
The smallest y can be is 1, in which case

{{{1= 3 333 333 333 333-2n }}}

{{{2n = 3 333 333 333 332}}}

{{{n = 1666666666666}}}

So n can take on integers from 1 through 1 666 666 666 666
inclusive.

Answer: 1 666 666 666 666 

Edwin</pre>