Question 1077750
SOLUTION
PERIMETER OF RECTANGLE=2(l+b)
2(l+b)=84...i
2[(l+3)+2b)=120...ii
solving
l+b=42
l=42-b...iii
subtutute l in eqn ii
l+3+2b=60
42-b+3+2b=60
b=15
put b in eqn iii
l=42-15=27
Length =27, Breadth=15
check:2(l+b)=84
2(27+15)=84


check eqn ii yourself