Question 1077747
Since {{{ 1000^2 = 1000000 }}}  and {{{ 2000^2 = 4000000 }}}
every integer in the interval [1001, 1999] has a square that falls in the range {{{ 1000000 < n^2 < 4000000}}}

1999-1001+1 = {{{highlight(999)}}} integers.