Question 95071
2a+6/(a^2+6a+9)+1/a+3 
:
Assume you mean:
{{{((2a+6))/((2a^2+6a+9))}}} + {{{1/((a+3))}}}
:
Factoring won't help here. 
1. Put the two fractions over a common denominator, 
2. FOIL (2a+6)(a+3)
3. Combine like terms:
{{{((2a+6)(a+3) + (2a^2+6a+9))/((2a^2+6a+9)(a+3))}}} =  {{{((2a^2 + 12a + 18) + (2a^2+6a+9))/((2a^2+6a+9)(a+3))}}} = {{{((4a^2 + 18a + 27))/((2a^2+6a+9)(a+3))}}}
:
That's about all you can do with it. Nothing will factor.