Question 1077631
Below is what I have so far:

A basketball team sells tickets that cost $10, $20, or, for VIP seats, $30. The team has sold 3343 tickets overall. It has sold 113 more $20 tickets than $10 tickets. The total sales for $62,350. How many tickets have been sold? 
How many $10 tickets were sold? 
How many $20 tickets were sold? 
How many $30 tickets were sold?

I have been able to figure out:
3343 tickets overall
113 more $20 tickets than $10 tickets
62,350 total sales

$10 = a
$20 = b
$30 = c

a + b + c = 3343
b = a + 113
10a + 20b + 30c = 62350

This is where I am stuck:
a+2b+3c= (should this be 140)?

What do I need to do from here, specifically, in order to get the three ticket sold amounts?  Please be specific in your steps.
<pre>No!! {{{a + 2b + 3c <> 140}}} 
$10 = a
$20 = b
$30 = c

a + b + c = 3,343 ------ eq (i)
b = a + 113 ------- eq (ii)
10a + 20b + 30c = 62,350______10(a + 2b + 3c) = 10(6,235)_____a + 2b + 3c = 6,235 ------- eq (iii)
a + a + 113 + c = 3,343 ------- Substituting a + 113 for b in eq (i)
2a + c = 3,230 ------ eq (iv)

a + 2(a + 113) + 3c = 6,235 ------- Substituting a + 113 for b in eq (iii)
a + 2a + 226 + 3c = 6,235 
3a + 3c = 6,009 ------ eq (v)
- 6a - 3c = - 9,690 ----- Multiplying eq (iv) by - 3 ------ eq (vi)
- 3a = - 3,681------ Adding eq (vi) & (v)
{{{highlight_green(matrix(1,11, "a,", or, number, of, "$10", tickets, sold, "=", "- 3,681"/(- 3), "=", "1,227"))}}}
You should now be able to find the number of $20 and $30 tickets sold!!
<b><u>Word of advice:</b></u> STAY away from ANY and EVERYTHING that the other person tells you to do. You will never, in a million years,
                find the correct answer if you so choose to not heed my warning!