Question 95052
length = l
width = w
diagonal = d
l^2 + w^2 = d^2= 4^2=16
l=w+1
then (w+1)^2 + w^2 = 16 then w^2 +2w+1 +w^2=16 then 2w^2 + 2w+1 =16
2w^2 + 2w=15