Question 1077601
V=V_0*e^(-k*t)
Where V_0 is the initial value of the computer, k is the depreciation constant, and t is the number of years.

In this case, V_0 is $150 and k is 12.5% or 0.125

so [V=150*exp(-0.125*t)]

 The max value of V is $150, so the computer will only go down in price as the years go down, so the value of the computer will [NEVER] reach $600.

In 10 years: V(10)=150*exp(-0.125*10)= [$42.97]