Question 1077519
Given that 
{{{3^(-n) = 0.2}}}........solve for {{{n}}}

{{{1/3^n = 2/10}}}

{{{1/3^n = 1/5}}} =>if nominators same, denominators are same too

{{{3^n = 5}}}...........take log of both sides

{{{log(3^n) = log(5)}}}

{{{n*log(3) = log(5)}}}

{{{n = log(5)/log(3)}}}

{{{n = 1.46497}}}


Find the value of {{{(3^4)^n=3^(4n) }}}:

{{{(3)^(4*1.46497) =624.99=625}}}