Question 1077441
{{{2^x=3/16}}}

{{{2^x=3*2^(-4)}}}

If choose base ten,

{{{log((2^x))=log((3))+log((2^(-4)))}}}

{{{x*log((2))=log((3))-4*log((2))}}}

{{{x=(log((3))-4*log((2)))/log((2))}}}


Now either check in log table or use electronic calculator.  


If you wanted to use base two instead, you would then need Change of Base formula for {{{log(2,3)}}}.