Question 1077099
I am supposed to find the zeros of {{{f(x)=3x^3-4x^2+8x+8}}} and I know there are going to be complex zeroes, I just do not know how to start factoring it so that I can solve it.
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There are no integer factors.
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Look for a fractional zero as Edwin said.
Make an Excel sheet if you have it.
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<pre>

3x^3-4x^2+8x+8	
	
-2	        -48
-1.666666667	-30.33333333
-1.333333333	-16.88888889
-1	        -7
-0.666666667	 0
-0.333333333	 4.777777778
0	         8
0.333333333	 10.33333333
</pre>
-2/3 is a zero.
Divide by (3x+2), then solve the quadratic.