Question 1077062
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Let x be the value exactly half-way between L and W: x = {{{(L+W)/2}}}.

Then L = x+2, W = x-2.


Then the equation LW = 36 takes the form (x+2)*(x-2) = 36,   or

{{{x^2 - 4}}} = 36,   or   {{{x^2}}} = 40,   or   x = {{{sqrt(40)}}} = {{{2*sqrt(10)}}}.


Thus L = {{{2 + 2*sqrt(10)}}},  W = {{{2*sqrt(10)-2}}}.


<U>Answer</U>.  The dimensions of the rectangle are  {{{2*sqrt(10)+2}}} meters (the length)  and  {{{2*sqrt(10)-2}}} meters (the width).
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