Question 1077070
If car B travels at {{{ 35 }}} mi/hr, it will never catch up
to car A -it will always be {{{ 200 }}} ft behind, so any
speed greater than {{{ 35 }}} mi/hr will allow it to catch up
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Suppose B's speed  = {{{ 45 }}} mi/hr
Let {{{ d }}} = distance that B travels until it catches A
Let {{{ t }}} = time in hrs for B to catch A
Convert {{{ 200 }}} ft to miles: {{{ 200/5280 }}}
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Equation for A:
(1) {{{ d - 200/5280 = 35t }}}
Equation for B:
(2) {{{ d = 45t }}}
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Plug (2) into (1)
(1) {{{ d - 200/5280 = 35t }}}
(1) {{{ 45t - 200/5280 = 35t }}}
(1) {{{ 10t = 200/5280 }}}
(1) {{{ t = 20/5280 }}}
(1) {{{ t = .003788 }}} hrs
Convert hrs to sec
{{{ .003788*3600 = 13.64 }}}
B will catch A in 13.64 sec
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Plug back into (2) to find {{{ d }}}
Hope this helps