Question 94994
Ok, you can start by recalling that the "domain" of a function is the set of all possible values of the independent variable.
In your function {{{y = 4-5x}}} x is the independent variable (y is the dependent variable).
So you can answer the problem by assigning to x in your function, each of the given values of the domain, then solve for the corresponding value of y.

{{{y = 4-5x}}} Let x = -2 The first of the given values in the domain.
{{{y = 4-5(-2)}}}
{{{y = 4-(-10)}}}
{{{y = 4+10}}}
{{{y = 14}}} This is the value of y that corresponds to the domain value of -2.
Now you repeat this process for each of the remaining given values of the domain.
{{{y = 4-5x}}} Let x = -1 The second value in the set.
{{{y = 4-5(-1)}}}
{{{y = 4-(-5)}}}
{{{y = 4+5}}}
{{{y = 9}}}

{{{y = 4-5x}}} Let x = 1 The third value.
{{{y = 4-5(1)}}}
{{{y = 4-5}}}
{{{y = -1}}}

You proceed in this fashion until you have used all five values of the given set.

{{{y = 4-5x}}} Let x = 3.
{{{y = 4-5(3)}}}
{{{y = 4-15}}}
{{{y = -11}}}

You should be able to finish these.