Question 94961
this isn't like ebay where positive feedback is almost a necessity...


dividing by a fraction is the same as multiplying by the inverse of the fraction


{{{((x-6)/(x+2))((x+5)/(x+8))=((x-6)(x+5))/((x+2)(x+8))}}} ... FOILing gives {{{(x^2-x-30)/(x^2+10x+16)}}}