Question 1076543
For the square:  
         perimeter=p=4s     
         area = {{{s^2}}}

For the circle:
          circumference = c = {{{2(pi)r}}}
          area = {{{(pi)r^2}}}

The areas are equal (given):
                {{{(pi)r^2 = s^2}}}
Taking sqrt of both sides:
                  {{{ sqrt(pi)r = s }}}

Now p can be expressed in terms of r:
                {{{ p = 4s = 4sqrt(pi)r }}}

Since  {{{4sqrt(pi) > 7 }}} and {{{2(pi) < 7 }}} ,   {{{ highlight(p>c) }}}