Question 1057558
.74=e^-0.00012t
ln 0.74=ln e^-0.00012t
ln 0.74=-0.00012t ln e
-0.3011050927839216142506551168791/-0.00012=t
t=2509.209 years as the age of the bone. &#9786;&#9786;&#9786;&#9786;