Question 1076392
First term, a.
common difference, d.


General term: {{{a+d(n-1)}}}


Tenth term,  {{{a+d(10-1)=a+9d}}}.
Sum of the ten terms is 190:  {{{(a+a+9d)(10/2)=190}}}
{{{5(2a+9d)=190}}}
{{{2a+9d=38}}}



The sum of the fourth and eighth term exceeds the fifth term by 25.
{{{(a+d(4-1))+(a+d(8-1))-(a+d(5-1))=25}}}
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{{{a+3d+a+7d-a-4d=25}}}
{{{a+6d=25}}}


Solve this system for first term, a, and common difference, d:
{{{system(2a+9d=38,a+6d=25)}}}
You should be able to do that and find the first four terms.