Question 1076346

Solve by completing the square. The equation is 25x^2+30-12=0
<pre>If this is {{{25x^2 + 30x - 12 = 0}}}, then this is the correct way to solve by COMPLETING the square
{{{x^2 + (30/25)x - 12/25 = 0}}} ------- Dividing by 25
{{{x^2 + (6/5)x = 12/25}}} ------- Reducing {{{30/25}}}, and adding {{{12/25}}} to both sides
{{{x^2 + (6/5)x + ((1/2) * (6/5))^2 = 12/25 + ((1/2) * (6/5))^2}}} ------ Taking {{{(1/2)}}} of b, squaring it, and then adding the result to both sides
{{{x^2 + (6/5)x + (6/10)^2 = 12/25 + (6/10)^2}}}, reduced to: {{{x^2 + (6/5)x + (3/5)^2 = 12/25 + (3/5)^2}}}
{{{(x + 3/5)^2 = 12/25 + 9/25}}}
{{{(x + 3/5)^2 = 21/25}}}
{{{sqrt((x + 3/5)^2) = " "+- sqrt(21/25)}}} ------- Taking the square root of both sides
{{{x + 3/5 = ""+- sqrt(21)/5}}}
{{{highlight_green(matrix(1,8, x, "=", ""+- sqrt(21)/5 - 3/5, ",", or, x, "=", ""+- (sqrt(21) - 3)/5))}}}