Question 1076280
{{{df/dx=(2/3)(x^2+2x+3)^(-1/3)(2x+2)}}}
{{{df/dx=(4(x+1))/(3*root(3,(x^2+2x+3)))}}}
So,
{{{df/dx=(4(-1+1))/(3*root(3,((-1)^2+2(-1)+3)))}}}
{{{df/dx=(4(0))/(3*root(3,(1-2+3)))}}}
{{{df/dx=0}}}