Question 1076273
{{{y=-(x^2+2x-5)}}}

{{{y=-(x^2+2x+1-1-5)}}}

{{{y=-((x+1)^2-6)}}}

{{{highlight(y=-(x+1)^2+6)}}}


-
Vertex is a maximum point  (-1,6).


Set {{{f(x)=y=0}}} and solve for x to find the x-intercepts.  YOU do that.


y-intercept?   {{{f(0)=-0^2-2*0+5}}} and simplify.


Symmetry Axis:  {{{x=-1}}}.