<PRE><B>Question 1076263</B>
&lt;pre&gt;&lt;b&gt;
{{{125x^3-1}}}

Write 125 as 5&lt;sup&gt;3&lt;/sup&gt;.

{{{5^3x^3-1}}}

Then write 5&lt;sup&gt;3&lt;/sup&gt;x&lt;sup&gt;3&lt;/sup&gt; as (5x)&lt;sup&gt;3&lt;/sup&gt; 

{{{(5x)^3-1}}}

Write 1 as 1&lt;sup&gt;3&lt;/sup&gt;

{{{(5x)^3-1^3}}}

Now substitute in the factoring formula for the difference 
of cubes:

{{{matrix(1,3,

A^3-B^3,&quot;&quot;=&quot;&quot;,(A-B^&quot;&quot;)(A^2+AB+B^2))}}}

with A = (5x) and B=1

{{{matrix(1,3,

(5x)^3-1^3,&quot;&quot;=&quot;&quot;,((5x)-1^&quot;&quot;)((5x)^2+(5x)1+1^2))}}}

So:

{{{matrix(1,3,

125x^3-1,&quot;&quot;=&quot;&quot;,(5x-1^&quot;&quot;)(25x^2+5x+1))}}}

Edwin&lt;/pre&gt;&lt;/b&gt;</PRE>