Question 1076197

how  to find the zero 2x^2-x-1
<pre>This should be in the form of an equation, as follows: {{{y = 2x^2 - x - 1}}}
{{{2x^2 - x - 1 = 0}}} --------- Substituting 0 for y
{{{(2x + 1)(x - 1) = 0}}} ----- Factoring TRINOMIAL on left
2x + 1 = 0       OR      x - 1 = 0
2x = - 1         OR      x = 0 + 1
{{{highlight_green(matrix(1,7, x, "=", - 1/2, or, x, "=", 1))}}}
This is the SIMPLEST and best method, if you're familiar with it.