Question 1073929
If the driver must be able to stop in 68 ft., then the maximum safe speed would be:
68=0.04v²+0.5v
6800=4v²+50v
4v²+50v-6800=0
2v²+25v-3400=0
Using the quadratic formula, we get two roots of 30.584219849 and -55.584219849.
Ignoring the negative answer, we get a maximum safe speed of 30.58 mph. &#9786;&#9786;&#9786;&#9786;