Question 94805
All 3 coefficients are divisable by 2, so{{{2(7x^2-10x+3)}}}
we know a lot. Both signs will be the same because there is a + in front of the 3. Both signs will be (-) because of the (-) in front of the 10. Both  7 and 3 are prime numbers so we wont be dividing those up.
2(7x-3)(x-1)This works.
EdJones