Question 1076102
Let n be the amount of 80% alloy. Then the 30% alloy is 50-n. So:
.8n+.3(50-n)=.68(50)
.5n+15=34
.5n=19
n=38
He needs 38 gms of 80% alloy, and 12 gms 30% alloy. &#9786;&#9786;&#9786;&#9786;