Question 1076100
-2x^2+28x=26
(28/2)^2=196 **** Should be (b/2a)^2 = 49
-2x^2+28x+196=26+196
since you cannot take the square root of a negative, i got no real solution
 
√-2x^2 = no real solutions
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-2x^2+28x=26
I would start with this:
Divide by -2
x^2 - 14x = -13
Make it easier.