Question 1076076

c. 
{{{4^(2x)=(1/2)^(x+5)}}}

{{{4^(2x)=1^(x+5)/2^(x+5)}}}........since {{{1^(x+5)}}} always will be equal {{{1}}}, we have 

{{{(2^2)^(2x)=1/2^(x+5)}}}

{{{2^(4x)=2^(-(x+5))}}}

{{{2^(4x)=2^(-x-5)}}}

{{{4x=-x-5}}}

{{{4x+x=-5}}}

{{{5x=-5}}}

{{{x=-5/5}}}

{{{x=-1}}}