Question 1076021
{{{a[n]=2*a[n-1]}}}
So,
{{{a[2]=2*a[1]}}}
{{{a[3]=2*a[2]}}}
{{{a[4]=2*a[3]}}}
{{{a[5]=2*a[4]}}}
{{{a[6]=2*a[5]}}}
Once you know a term, the next term is double that term,
So,
{{{a[2]=2*3=6}}}
So then,
{{{a[3]=2*a[2]=2*6}}}
Calculate that and then do the rest of them the same way.