Question 1076009
Use a substitution,
{{{u=sin(x)}}}
.
.
{{{4u^2+7u-2=0}}}
{{{(u+2)(4u-1)=0}}}
Two "u" solutions:
{{{u+2=0}}}
{{{u=-2}}}
{{{sin(x)=-2}}}
No x solution here.
{{{4u-1=0}}}
{{{4u=1}}}
{{{u=1/4}}}
{{{sin(x)=1/4}}}
There are two solutions here:
{{{x=14.5}}} and {{{x=165.5}}}