Question 1075979

I don't understand this problem: If N is the first of six consecutive odd numbers and 42 is the average of these numbers, find N.
<pre>Since N is the 1st number, then others are: N + 2, N + 4, N + 6, N + 8, and N + 10
We then get: {{{((N) + (N + 2) + (N + 4) + (N + 6) + (N + 8) + (N + 10))/6 = 42}}}
{{{matrix(1,3, (6N + 30)/6, "=", 42)}}} 
6N + 30 = 252 ------- Cross-multiplying
6N = 222
N, or 1st number = {{{highlight_green(matrix(1,3, 222/6, or, 37))}}}
That's all!! Nothing CONFUSING and/or COMPLEX!