Question 1075827
<pre>
The complement event is for all of them to have different
birthdays.  Suppose they are Tom, Dick and Harry.

So we get the probability that they all have different 
birthdays.

There are 365 possible birthdays for Tom.
That leaves 364 possible birthdays for Dick.
That leaves 363 possible birthdays for Harry. 

So the number of ways they can all have different birthdays 
is {{{365*364*363}}}

The number of ways they can have ANY birthdays, different
or not, is {{{365*365*365}}}

So the probability that all three have different birthdays is

{{{(365*364*363)/(365*365*365)=132132/133225}}}

So the probability that at least two have the same birthday
is

{{{1-132132/133225=1093/133225="0.008204165884781384875211109026083693000562957402889848001..."}}}

Edwin</pre>