Question 94855
Assuming that this a table of values, the work is as follows.
In this problem, you will just be inserting the numbers {-2, 0, and 3} into the x spot of the equation.
So:
y = 6 - 1/2(-2)
y = 6 + 1 (which is equiavlent to y = 6 - -1, because double negatives equal a positive!)
y = 7
So, 7 goes in the first blank, next to -2.
y = 6 - 1/2(0)
y = 6 - 0
y = 6
So, 6 goes in the second blank, next to 0.
y = 6 - 1/2(3)
y = 6 - 1.5
y = 4.5
So, 4.5, or 4 1/2, goes in the third blank, next to 3.
Remember to always check your answers after you finish a problem to make sure they're correct! It's better to take that extra time than to get them wrong on an assignment or test! Good luck!