Question 1075739
x,y,z are numbers
xy=24
yz=48
xz=32

x=(24/y)
(24/y)*z=32
yz=48, so z=(48/y)
(24/y)(48/y)=32
(1152/y^2)=32
32y^2=1152
y^2=36
y=6
x=4
z=8