Question 94818
The equation of the line with y-intercept of 3 and perpendicular to the graph of 2x+y=5 is? 
:
y intercept occurs when x = 0, therefore the equation in the form y = mx + b
would be y = mx + 3
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Now we want to find the slope (m) of the given equation:
Put equation in the slope/intercept (y = mx + b) form:
2x + y = 5
y = -2x + 5
The slope m = -2
:
Slope relationship between perpendicular lines is given as: m1*m2 = -1
Assume the m1 = -2 from the above equation, 
find m2 (the slope of the perpendicular line) y = mx + 3
:
-2 * m2 = -1
Divide both sides by -1 and you have:
m2 = -1/-2
m2 = +1/2
:
The equation of the perpendicular line: y = {{{1/2}}}x + 3
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It will help you to memorize the perpendicular lines slope relationship 
m1 * m2 = 1, and that y intercept occurs when x = 0