Question 1075653
{{{(3-x)/(x^2-9)=-3}}}
factor the denominator, factor out -1 in the numerator
{{{(-1(x - 3))/((x-3)(x+3)) = -3}}}
Cancel (x-3)
{{{(-1)/(x+3) = -3}}}
multiply both sides by (x+3),get rid of the denominator
-1 = -3(x+3)
-1 = -3x - 9
3x = -9 + 1
3x = -8
x = {{{-8/3}}} a unique solution
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Check this on your calc, enter:
{{{(3-(-8/3))/((-8/3)^2-9)}}}