<PRE><B>Question 1075427</B>
with all 11 distinguishable from one another, there are 11C4 or 330 different ways to draw them.
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draws that contain one of each are
3C1*3C1*3C1*2C1=54
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2 red marbles can occur in 6 possible ways in drawing 4 (4C2) plus 4 ways in 4C3, so 10 ways total.
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At least one green can occur 4 ways for 1, 6 ways for 2, and 4 ways for 3.  If one green is chosen, there are 3 other marbles left out of 5 that can be chosen or 5C3=10.  There are 10 ways.
For 2 green, there are now 2 other marbles out of 5 allowed or 10 ways.
For 3 green, there is now one other choice out of 5 or 5 ways.
There are 25 ways to choose at least 1 green and no red.
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