Question 1075592
{{{x^2+6mx+m=(x+a)^2}}}
{{{x^2+6mx=x^2+2ax+a^2}}}
So,
{{{2a=6m}}}
{{{a=3m}}}
and
{{{m=a^2}}}
So,
{{{a=3a^2}}}
{{{a=1/3}}}
So then,
{{{1/3=3m}}}
{{{m=1/9}}}