Question 1075604
Two ways to interpret this problem.
One die rolled twice: (1/2) probability even* (1/3) larger than 4 (5 and 6)=1/6 total probability.
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Two dice (because plural form of noun die).
First roll is even
That occurs when 2,4,6,8,10,12, and that is (1/2) as well but second part, greater than 4 is 30/36 or 5/6.  That joint probability is (1/2)*(5/6)=(5/12)
I suspect the first solution is what is asked for.