Question 1075567
Yes,
{{{P(X)=C(13,X)*(0.4)^X*(1-0.4)^(13-X)}}} where X is the number of wins.
Make up a chart using EXCEL or by hand.
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*[illustration frt4.JPG].
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Here's my chart from EXCEL. 
As a check the sum of the probabilities should equal 1.
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a)Losing 13 means winning 0.
{{{P(0)=0.0013}}}
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b){{{P(5)=0.2214}}}
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c) {{{P=P(5)+P(6)=0.4181}}}
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d) Winning 1 games means not losing all of them so use the complement of the answer to a).
{{{P=1-0.0013}}}
{{{P=0.9987}}}