Question 1075565
For the 1st card, there are {{{ 13 }}} ways to get a heart
so P(H[1]) = {{{ 13/52 }}} 
For the 2nd card, there are {{{ 39 }}} ways to NOT get a heart
so P(X[2]) = {{{ 39/51 }}}
For the 3rd card, there are {{{ 38 }}} ways to NOT get a heart
so P(x[3]) = {{{ 38/50 }}}
For the 4th card, there are {{{ 12 }}} ways to get a heart
so P(H[4]) = {{{ 12/49 }}}
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You want all of these, so multiply probabilities
{{{ ( 13/52 )*( 39/51 )*( 38/50 )*( 12/49 ) = 231192/6497400 }}}
{{{ 231192/6497400 = .03558 }}}
Definitely get a 2nd opinion on this!!