Question 1075548
Unclear but intent could be base five.


{{{log(5,(2x+1))+log(5,(x+2))=1}}}

{{{log(5,(2x+1)(x+2))=1}}}

{{{5^1=(2x+1)(x+2)}}}


{{{2x^2+5x+2-5=0}}}


{{{2x^2+5x-3=0}}}


{{{(2x-1)(x+3)=0}}}


{{{x=1/2}}}